document.write( "Question 950339: The length of a rectangle is four feet more than twice its width. If the area of the rectangle is 160 square feet, its length is _____ feet? \n" ); document.write( "

Algebra.Com's Answer #580368 by Fombitz(32388) $\"\"$ $\"About$

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For a rectangle,
\n" ); document.write( " $\"A=L%2AW=160\"$
\n" ); document.write( " $\"%28W%2B4%29W=160\"$
\n" ); document.write( " $\"W%5E2%2B4W=160\"$
\n" ); document.write( " $\"W%5E2%2B4W%2B4=160%2B4\"$
\n" ); document.write( " $\"%28W%2B2%29%5E2=164\"$
\n" ); document.write( " $\"W%2B2=0+%2B-+sqrt%28164%29\"$
\n" ); document.write( " $\"W=-2+%2B-+2sqrt%2841%29\"$
\n" ); document.write( "Since we're only interested in the positive solution,
\n" ); document.write( " $\"W=-2%2B2sqrt%2841%29\"$
\n" ); document.write( "So then,
\n" ); document.write( " $\"L=-2%2B2sqrt%2841%29%2B4\"$
\n" ); document.write( " $\"L=2%2B2sqrt%2841%29\"$
\n" ); document.write( " \n" ); document.write( "

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