document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=950405>Question 950405</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 54, and five times the larger added to twice the smaller equals 225. Find the number<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #580341 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=580341\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a and b are the numbers<BR>\n" );
document.write( "a+b=54<BR>\n" );
document.write( "a=54-b<BR>\n" );
document.write( "5a+2b=225 Substitute for a<BR>\n" );
document.write( "5(54-b)+2b=225<BR>\n" );
document.write( "270-5b+2b=225 Subtract 225 from each side.<BR>\n" );
document.write( "45-3b=0 Subtract 3b from each side.<BR>\n" );
document.write( "45=3b Divide each side by 3<BR>\n" );
document.write( "15=b One of the numbers is 15<BR>\n" );
document.write( "a=54-b=54-15=39 The other number is 39<BR>\n" );
document.write( "ANSWER: The numbers are 15 and 39<BR>\n" );
document.write( "CHECK<BR>\n" );
document.write( "5a+2b=225<BR>\n" );
document.write( "5(39)+2(15)=225<BR>\n" );
document.write( "195+30=225<BR>\n" );
document.write( "225=225<BR>\n" );
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