document.write( "Question 950397: how do I go about solving these linear equations using substitution
\n" ); document.write( "4x-y=5
\n" ); document.write( "4x+4y=-4
\n" ); document.write( "I know I have to add to both sides of the first one but I do not remember which sides or where to go from there.
\n" ); document.write( "

Algebra.Com's Answer #580333 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
go about solving these linear equations using substitution
\n" ); document.write( "4x-y=5
\n" ); document.write( " 4x+4y=-4
\n" ); document.write( "----
\n" ); document.write( "Modify::
\n" ); document.write( "y = 4x-5
\n" ); document.write( "x + y = -1
\n" ); document.write( "-------------------
\n" ); document.write( "Substitute for \"y\" and solve for \"x\"::
\n" ); document.write( "x + 4x-5 = -1
\n" ); document.write( "----
\n" ); document.write( "5x = 4
\n" ); document.write( "x = 4/5
\n" ); document.write( "----
\n" ); document.write( "Solve for \"y\"
\n" ); document.write( "x + y = -1
\n" ); document.write( "4/5 + y = -1
\n" ); document.write( "y = -9/5
\n" ); document.write( "--------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "--------------
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