document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=950397>Question 950397</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do I go about solving these linear equations using substitution <BR>\n" );
document.write( "4x-y=5<BR>\n" );
document.write( "4x+4y=-4<BR>\n" );
document.write( "I know I have to add to both sides of the first one but I do not remember which sides or where to go from there.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #580332 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=580332\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how do I go about solving these linear equations using substitution <BR>\n" );
document.write( "4x-y=5 --> y = 4x-5<BR>\n" );
document.write( "4x+4y=-4<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Sub for y in the 2nd eqn<BR>\n" );
document.write( "4x + 4(4x-5) = -4<BR>\n" );
document.write( "x + 4x-5 = -1<BR>\n" );
document.write( "5x = 4<BR>\n" );
document.write( "x = 4/5<BR>\n" );
document.write( "------<BR>\n" );
document.write( "y = -9/5<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );