document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=80881>Question 80881</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor\r<BR>\n" );
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document.write( "5xSQUARED-13x+6\r<BR>\n" );
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document.write( "could u show me how u got this please </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #58032 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=58032\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5xSQUARED-13x+6 <BR>\n" );
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document.write( "Think of two number whose product is 5*6=30 <BR>\n" );
document.write( "and whose sum is -13.<BR>\n" );
document.write( "The numbers are -3 and -10<BR>\n" );
document.write( "Replace -13x with the terms -3x and -10x to get:<BR>\n" );
document.write( "5x^2-3x-10x+6=0<BR>\n" );
document.write( "Factor the 1st two and the last two terms separately to get:<BR>\n" );
document.write( "x(5x-3)-2(5x-3)=0<BR>\n" );
document.write( "(5x-3)(x-2)=0<BR>\n" );
document.write( "x=3/5 or x=2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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