document.write( "Question 950288: Seven years ago Fatima was six times as old as Bernice. In one year,she will only be twice as old as Bernice.What will be Fatima's current age? \n" ); document.write( "
Algebra.Com's Answer #580305 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! let f = Fatima's present age \n" ); document.write( "Let b = Bernice's age \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement \n" ); document.write( ": \n" ); document.write( " Seven years ago Fatima was six times as old as Bernice. \n" ); document.write( "f - 7 = 6(b - 7) \n" ); document.write( "f - 7 = 6b - 42 \n" ); document.write( "f = 6b - 42 + 7 \n" ); document.write( "f = 6b - 35 \n" ); document.write( ": \n" ); document.write( "In one year, she will only be twice as old as Bernice. \n" ); document.write( "f + 1 = 2(b+1) \n" ); document.write( "f + 1 = 2b + 2 \n" ); document.write( "f = 2b + 2 - 1 \n" ); document.write( "f = 2b + 1 \n" ); document.write( "Replace f with (6b-35) \n" ); document.write( "6b - 35 = 2b + 1 \n" ); document.write( "6b - 2b = 1 + 35 \n" ); document.write( "4b = 36 \n" ); document.write( "b = 36/4 \n" ); document.write( "b = 9 yrs is B's present age \n" ); document.write( "find f \n" ); document.write( "f =2(9) + 1 \n" ); document.write( "f = 19 yrs is F's age \n" ); document.write( ": \n" ); document.write( "; \n" ); document.write( "Check this in the statement \n" ); document.write( "\"In one year,she will only be twice as old as Bernice.\" \n" ); document.write( "19 + 1 = 2 (9 + 1)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "What will be Fatima's current age? \n" ); document.write( " |