document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=950336>Question 950336</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chef is using a mixture of two brands of Italian dressing. The first brand contains <BR>\n" );
document.write( "8%<BR>\n" );
document.write( " vinegar, and the second brand contains <BR>\n" );
document.write( "13%<BR>\n" );
document.write( " vinegar. The chef wants to make <BR>\n" );
document.write( "310<BR>\n" );
document.write( " milliliters of a dressing that is <BR>\n" );
document.write( "9%<BR>\n" );
document.write( " vinegar. How much of each brand should she use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #580292 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=580292\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's call one brand a and the other b.\r<BR>\n" );
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document.write( "a + b = 310. Therefore, a = 310 - b. And,<BR>\n" );
document.write( ".08a + .13b = .09(310) Let's substitute in this equation with what we learned on the first equation (we learned that a= 310-b):\r<BR>\n" );
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document.write( ".08(310-b) + .13b = .09(310) Let's simplify, multiply:<BR>\n" );
document.write( "24.8 - .08b + .13b = 27.9 Subtract 24.8, both sides:<BR>\n" );
document.write( "- .08b + .13b = 3.1 Subtract on the left:<BR>\n" );
document.write( ".05b = 3.1 Divide both sides by .05:<BR>\n" );
document.write( "b = 62 OK, we need 62ml of .13 and 300 - 62 = 238ml of the .08 solution.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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