document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=950350>Question 950350</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mary can jog, on average, 2 miles per hour faster than her husband, James. James can jog 6.6 miles in the same amount of time it takes mary to jog 9 miles. Mary can jog____ miles per hour? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #580285 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=580285\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> J=Jame's rate; M=Mary's rate=J+2mph<BR>\n" );
document.write( "6.6 mi/J=9 mi/M Substitute for M<BR>\n" );
document.write( "6.6 mi/J=9 mi/J+2 Multiply each side by (J)(J+2) (cancel both denominators)<BR>\n" );
document.write( "6.6 mi(J+2mph)=9 mi(J)<BR>\n" );
document.write( "6.6J+13.2=9J Subtract 6.6J from each side.<BR>\n" );
document.write( "13.2=2.4J Divide each side by 2.4<BR>\n" );
document.write( "5.5mph=J James jogs 5.5 mph.<BR>\n" );
document.write( "M=J+2mph=5.5mph+2mph=7.5 mph ANSWER: Mary jogs 7.5 mph.<BR>\n" );
document.write( "CHECK <BR>\n" );
document.write( "James jogs 6.6 mi while Mary jogs 9 mi<BR>\n" );
document.write( "6.6 mi/J=9 mi/M<BR>\n" );
document.write( "6.6 mi/5.5 mph=9 mi/7.5 <BR>\n" );
document.write( "1.2 hrs=1.2 hrs </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );