document.write( "Question 80830: Two vagabonds who are 200 miles apart travel towards each other. If they start at 2 p.m. and meet at 6 p.m., and one vagabond is traveling 10 miles per hour faster than the other, what are the speeds of both vagabonds?\r
\n" ); document.write( "\n" ); document.write( "I tried using rate x time = distance like our teacher said, and this is what i got::
\n" ); document.write( "((Vagabond A, Vagabond B))\r
\n" ); document.write( "\n" ); document.write( "..........(r)........(t)..=..d
\n" ); document.write( "A........x
\n" ); document.write( "B........x+10
\n" ); document.write( "total................4h.....200mi\r
\n" ); document.write( "\n" ); document.write( "Then i divided 200 by 4 and got 50, so I got 50 mph and 60 mph... am I right?\r
\n" ); document.write( "\n" ); document.write( "Thank You!\r
\n" ); document.write( "\n" ); document.write( "Jamie
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Algebra.Com's Answer #58024 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Let's check your answer. One vagabond is going at a rate of 50 miles per hour. The time
\n" ); document.write( "at this rate is 4 hours (2 pm to 6 pm). In that 4 hour period at 50 miles per hour, that
\n" ); document.write( "vagabond travels the full 200 miles by itself. If that doesn't seem right, it means that
\n" ); document.write( "your answer is incorrect because the second vagabond wasn't even taken into consideration.
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\n" ); document.write( "Here's the way to do the problem.
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\n" ); document.write( "Use the distance formula for the vagabond that travels at the unknown rate R. When you do you
\n" ); document.write( "get that the distance (D1) for the first vagabond is:
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\n" ); document.write( "D1 = R*T
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\n" ); document.write( "At this point we know that T is 4 hours. So we can substitute 4 for T and the equation
\n" ); document.write( "then becomes:
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\n" ); document.write( "D1 = R*4 = 4R
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\n" ); document.write( "Now let's do the same thing for the second vagabond. It has a rate equal to the rate of
\n" ); document.write( "the first vagabond plus 10 miles per hour, so its rate is R+10. It also travels for 4 hours.
\n" ); document.write( "If the distance traveled by this second vagabond is D2 then its distance equation is:
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\n" ); document.write( "D2 = (R+10)*4
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\n" ); document.write( "Multiply out the right side and you get:
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\n" ); document.write( "D2 = 4R + 40
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\n" ); document.write( "Now recognize that when the two vagabonds meet, the total distance (D1 + D2) that they
\n" ); document.write( "travel is 200 miles. So lets add our two distance equations:
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\n" ); document.write( "D1 = 4R
\n" ); document.write( "D2 = 4R + 40
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\n" ); document.write( "When you add these vertically you get:
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\n" ); document.write( "D1 + D2 = 8R + 40
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\n" ); document.write( "But we already noted that D1 + D2 is 200 miles. So we can substitute 200 for D1 + D2 and
\n" ); document.write( "we get:
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\n" ); document.write( "200 = 8R + 40
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\n" ); document.write( "Get rid of the 40 on the right side by subtracting 40 from both sides. When you do that the
\n" ); document.write( "equation becomes:
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\n" ); document.write( "160 = 8R
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\n" ); document.write( "Finally, solve for R by dividing both sides by 8 and you get:
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\n" ); document.write( "R = 160/8 = 20 miles per hour
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\n" ); document.write( "So the rate of the first vagabond is 20 miles per hour and the rate of the second vagabond
\n" ); document.write( "is 10 miles per hour faster or 30 miles per hour.
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\n" ); document.write( "Let's check these answers.
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\n" ); document.write( "At 20 miles per hour, in 4 hours the first vagabond goes 80 miles toward the second vagabond.
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\n" ); document.write( "Meanwhile at 30 miles per hour, in 4 hours the second vagabond goes 120 miles toward the
\n" ); document.write( "first vagabond.
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\n" ); document.write( "This combination means that in the 4 hours the two together cover 80 + 120 miles and when
\n" ); document.write( "that is done they meet having covered the 200 miles between them when they started out.
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\n" ); document.write( "Hope this helps you to understand the problem and how your teacher said you could use
\n" ); document.write( "the distance formula to solve it.
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