document.write( "Question 950304: what is the equation in logarithmic form for 16=(1/4)-2?
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Algebra.Com's Answer #580239 by Theo(13342)\"\" \"About 
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i believe you mean 16 = (1/4)^(-2)\r
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\n" ); document.write( "\n" ); document.write( "if you use your calculator to evaluate this equation, you will see that:\r
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\n" ); document.write( "\n" ); document.write( "16 = 16.\r
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\n" ); document.write( "\n" ); document.write( "this confirms the equation is true.\r
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\n" ); document.write( "\n" ); document.write( "the ^ symbol indicates exponentiation.\r
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\n" ); document.write( "\n" ); document.write( "the equation is 16 = (1/4)^-2\r
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\n" ); document.write( "\n" ); document.write( "this is in the form of y = b^x, where:\r
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\n" ); document.write( "\n" ); document.write( "y = 16
\n" ); document.write( "b = (1/4)
\n" ); document.write( "x = -2\r
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\n" ); document.write( "\n" ); document.write( "in general, y = b^x if and only if log(b,y) = x\r
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\n" ); document.write( "\n" ); document.write( "log(b,y) means log of y to the base of b.\r
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\n" ); document.write( "\n" ); document.write( "apply that to your problem and you get:\r
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\n" ); document.write( "\n" ); document.write( "16 = (1/4)^-2 if and only if log(1/4,16) = -2\r
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\n" ); document.write( "\n" ); document.write( "how do you confirm?\r
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\n" ); document.write( "\n" ); document.write( "use your calculator and the log conversion formula that tells you that:\r
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\n" ); document.write( "\n" ); document.write( "log(1/4,16) = log(16) / log(1/4).\r
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\n" ); document.write( "\n" ); document.write( "remember that log without mention of the base means the base is 10.\r
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\n" ); document.write( "\n" ); document.write( "log(16) / log(1/4) means log of 16 to the base of 10 divided by log of 1/4 to the base of 10.\r
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\n" ); document.write( "\n" ); document.write( "log to the base of 10 is the LOG function in your calculator.\r
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\n" ); document.write( "\n" ); document.write( "your equation becomes:\r
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\n" ); document.write( "\n" ); document.write( "log(16) / log(1/4) = -2\r
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\n" ); document.write( "\n" ); document.write( "use your calculator to get:\r
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\n" ); document.write( "\n" ); document.write( "-2 = -2\r
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\n" ); document.write( "\n" ); document.write( "this confirms the conversion is correct.\r
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