document.write( "Question 950262: if the length of a rectangle measure measure is twice as much as a width and the perimeter is 72 feet find the dimensions of the rectangle \n" ); document.write( "

Algebra.Com's Answer #580210 by jhaashok630(18) $\"\"$ $\"About$

You can put this solution on YOUR website!
length of a rectangle measure measure is twice as much as a width and the perimeter is 72 feet\r
\n" ); document.write( "\n" ); document.write( "Let x=width of rectangle
\n" ); document.write( " length = 2x
\n" ); document.write( " Perimeter = 72
\n" ); document.write( " 2l+2w=72\r
\n" ); document.write( "\n" ); document.write( " 4x+2x=72
\n" ); document.write( " x=12\r
\n" ); document.write( "\n" ); document.write( "length = 24 feet and width = 12 feet \n" ); document.write( "

\n" );