document.write( "Question 950239: Manny has $2.30 in dimes and quarters. The total number of coins is 2 less than twice the number of dimes. How many of each denomination does he have? \n" ); document.write( "
Algebra.Com's Answer #580197 by macston(5194)![]() ![]() You can put this solution on YOUR website! d= no. of dimes; q= no of quarters \n" ); document.write( "q=(2d-2)-d=(d-2) \n" ); document.write( "$0.10d+$0.25q=$2.30 Substitute for q \n" ); document.write( "$0.10d+$0.25(d-2)=$2.30 \n" ); document.write( "$0.10d+$0.25d-$0.50=$2.30 Add $0.50 to each side. \n" ); document.write( "$0.35d=$2.80 Divide each side by $0.35 \n" ); document.write( "d=8 ANSWER 1: There were 8 dimes. \n" ); document.write( "q=d-2=8-2=6 ANSWER 2: There were 6 quarters \n" ); document.write( "CHECK: \n" ); document.write( "$0.10d+$0.25q=$2.30 \n" ); document.write( "$0.10(8)+$0.25(6)=$2.30 \n" ); document.write( "$0.80+$1.50=$2.30 \n" ); document.write( "$2.30=$2.30 \n" ); document.write( " |