document.write( "Question 950239: Manny has $2.30 in dimes and quarters. The total number of coins is 2 less than twice the number of dimes. How many of each denomination does he have? \n" ); document.write( "
Algebra.Com's Answer #580197 by macston(5194)\"\" \"About 
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d= no. of dimes; q= no of quarters
\n" ); document.write( "q=(2d-2)-d=(d-2)
\n" ); document.write( "$0.10d+$0.25q=$2.30 Substitute for q
\n" ); document.write( "$0.10d+$0.25(d-2)=$2.30
\n" ); document.write( "$0.10d+$0.25d-$0.50=$2.30 Add $0.50 to each side.
\n" ); document.write( "$0.35d=$2.80 Divide each side by $0.35
\n" ); document.write( "d=8 ANSWER 1: There were 8 dimes.
\n" ); document.write( "q=d-2=8-2=6 ANSWER 2: There were 6 quarters
\n" ); document.write( "CHECK:
\n" ); document.write( "$0.10d+$0.25q=$2.30
\n" ); document.write( "$0.10(8)+$0.25(6)=$2.30
\n" ); document.write( "$0.80+$1.50=$2.30
\n" ); document.write( "$2.30=$2.30
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