document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=950238>Question 950238</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How to find the zero's of:<BR>\n" );
document.write( "P(x) = x^2 - x^2 - 6x<BR>\n" );
document.write( "and<BR>\n" );
document.write( "P(x) = x^4 - 3x + 2x\r<BR>\n" );
document.write( "\n" );
document.write( "Please explain how this is done\r<BR>\n" );
document.write( "\n" );
document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #580191 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39621)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=580191\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The two definitions for P(x) are not equal, so what you mean is not clear.  The zeros for the two different definitions could also be different.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The first definition is uninvolved and very simple.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The second definition <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%28x%5E3-3%2B2%29 ALIGN=MIDDLE  ALT=\"x%28x%5E3-3%2B2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%28x%5E3-1%29 ALIGN=MIDDLE  ALT=\"x%28x%5E3-1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%28x-1%29%28x%5E2%2Bx%2B1%29 ALIGN=MIDDLE  ALT=\"x%28x-1%29%28x%5E2%2Bx%2B1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and you could use polynomial division to uncover this.  You'd divide the cubic factor by  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x-1 ALIGN=MIDDLE  ALT=\"x-1\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "ROOTS:   0, 1, and two complex roots from the quadratic factor.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "FINDING THOSE LAST TWO ROOTS:<BR>\n" );
document.write( "General Solution of Quadratic Equation<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-1%2B-+sqrt%281%5E2-4%2A1%2A1%29%29%29%2F2 ALIGN=MIDDLE  ALT=\"%28-1%2B-+sqrt%281%5E2-4%2A1%2A1%29%29%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-1%2B-+sqrt%28-3%29%29%2F2 ALIGN=MIDDLE  ALT=\"%28-1%2B-+sqrt%28-3%29%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28%28-1%2B-+i%2Asqrt%283%29%29%2F2%29 ALIGN=MIDDLE  ALT=\"highlight_green%28%28-1%2B-+i%2Asqrt%283%29%29%2F2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );