document.write( "Question 80846: not sure how to type this but here goes\r
\n" ); document.write( "\n" ); document.write( "Let a random sample be taken of size n = 100 from a population with known standard deviation of o = 20 . Suppose that the mean of the sample is X = 37 . The approximate 68% confidence interval for the mean, u , of the population from which the sample was drawn is \r
\n" ); document.write( "\n" ); document.write( "n = n
\n" ); document.write( "o = Population standard deviation
\n" ); document.write( "X = Sample mean
\n" ); document.write( "u = population mean\r
\n" ); document.write( "\n" ); document.write( "I need some help on this question and my key board is short some keys. I hope that you can help thank you mirna. \n" ); document.write( "

Algebra.Com's Answer #58019 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let a random sample be taken of size n = 100 from a population with known standard deviation of o = 20 . Suppose that the mean of the sample is X = 37 . The approximate 68% confidence interval for the mean, u , of the population from which the sample was drawn is
\n" ); document.write( "-------------
\n" ); document.write( "E=z*sgma/sqrt(n)
\n" ); document.write( "E=0.994*20/sqrt(100)
\n" ); document.write( "E=0.994*2
\n" ); document.write( "E=1.988
\n" ); document.write( "-------------
\n" ); document.write( "CI: (x-bar-E,x-bar+E)
\n" ); document.write( "CI: (37-1.988, 37+1.988)
\n" ); document.write( "CI: (35.012,38.988)
\n" ); document.write( "=============
\n" ); document.write( "Let me know if this is too difficult to follow and I will add
\n" ); document.write( "some connecting comments.
\n" ); document.write( "=============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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