document.write( "Question 950226: The sum of the digits of a two-digit number is 13. If the digits are reversed, the original number is 45 less than the new number. Find the original number. \n" ); document.write( "
Algebra.Com's Answer #580171 by macston(5194)![]() ![]() You can put this solution on YOUR website! T=tens digit; N=ones digit \n" ); document.write( "T+N=13 \n" ); document.write( "T=13-N \n" ); document.write( "10T+N=(10N+T)-45 Substitute for T \n" ); document.write( "10(13-N)+N=10N+(13-N)-45 \n" ); document.write( "130-9N=9N-32 Add (9N+32) to each side. \n" ); document.write( "162=18N divide each side by 18. \n" ); document.write( "9=N ANSWER 1: The original units digit was 9 \n" ); document.write( "T=13-n=13-9=4 ANSWER 2:The original tens digit was 4 \n" ); document.write( "ANSWER The two digit number is 49 \n" ); document.write( "CHECK: \n" ); document.write( "49=94-45 \n" ); document.write( "49=49\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |