document.write( "Question 950226: The sum of the digits of a two-digit number is 13. If the digits are reversed, the original number is 45 less than the new number. Find the original number. \n" ); document.write( "
Algebra.Com's Answer #580171 by macston(5194)\"\" \"About 
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T=tens digit; N=ones digit
\n" ); document.write( "T+N=13
\n" ); document.write( "T=13-N
\n" ); document.write( "10T+N=(10N+T)-45 Substitute for T
\n" ); document.write( "10(13-N)+N=10N+(13-N)-45
\n" ); document.write( "130-9N=9N-32 Add (9N+32) to each side.
\n" ); document.write( "162=18N divide each side by 18.
\n" ); document.write( "9=N ANSWER 1: The original units digit was 9
\n" ); document.write( "T=13-n=13-9=4 ANSWER 2:The original tens digit was 4
\n" ); document.write( "ANSWER The two digit number is 49
\n" ); document.write( "CHECK:
\n" ); document.write( "49=94-45
\n" ); document.write( "49=49\r
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