document.write( "Question 950203: Coffee worth $ 1.05 per pound is mixed with coffee worth $0.85 per pound to obtain 20 pounds of mixture worth $0.90 per pound. How many pounds of each type of coffee were used? \n" ); document.write( "
Algebra.Com's Answer #580161 by stanbon(75887)\"\" \"About 
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Coffee worth $ 1.05 per pound is mixed with coffee worth $0.85 per pound to obtain 20 pounds of mixture worth $0.90 per pound. How many pounds of each type of coffee were used?
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\n" ); document.write( "Equation:
\n" ); document.write( "value + value = value
\n" ); document.write( "1.05x + 0.85(20-x) = 0.90*20
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\n" ); document.write( "105x + 85*20 - 85x = 90*20
\n" ); document.write( "20x = 5(20)
\n" ); document.write( "x = 5 lbs (amt. of $1.05 coffee needed)
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\n" ); document.write( "20-x = 15 lbs (amt. of $0.85 coffee needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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