document.write( "Question 950102: Seven years ago Fatima was six times as old as Bernice. In one year,she will only be twice as old as Bernice.What will be Fatima's current age? \n" ); document.write( "
Algebra.Com's Answer #580103 by macston(5194)\"\" \"About 
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F=Fatima's age; B=Bernice's age
\n" ); document.write( "F+1=2(B+1)
\n" ); document.write( "F+1=2B+2 Subtract 1 from each side.
\n" ); document.write( "F=2B+1
\n" ); document.write( "F-7 years=6(B-7 years) Substitute for F
\n" ); document.write( "2B+1-7years=6B-42 years Subtract 2B from each side.
\n" ); document.write( "-6 years=4B-42 years Add 42 years to each side.
\n" ); document.write( "36 years=4B Divide each sidde by 4.
\n" ); document.write( "9 years=B Bernice is 9 years old.
\n" ); document.write( "F+1 year=2(B+1 year)
\n" ); document.write( "F+1 year=2(9 years+1 year)
\n" ); document.write( "F+1 year=20 years Subtract year from each side
\n" ); document.write( "F=19 years ANSWER: Fatima is 19 years old.
\n" ); document.write( "CHECK:
\n" ); document.write( "7 years ago Fatima was 6 times as old as Bernice
\n" ); document.write( "F-7 years=6(B-7 years)
\n" ); document.write( "19 years-7 years=6(9 years-7years)
\n" ); document.write( "12 years=6(2 years)
\n" ); document.write( "12 years=12 years\r
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