document.write( "Question 949989: Working together, Carmel and Menchie can encode a document in 3 hours. Working alone, Menchie can do the job in 7 hours. How long does it takes Carmel to do the job working alone? \n" ); document.write( "

Algebra.Com's Answer #580081 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Working together, Carmel and Menchie can encode a document in 3 hours.
\n" ); document.write( " Working alone, Menchie can do the job in 7 hours.
\n" ); document.write( " How long does it takes Carmel to do the job working alone?
\n" ); document.write( ":
\n" ); document.write( "let c = amt of time by Carmel to do the job alone
\n" ); document.write( "let the completed job = 1
\n" ); document.write( ":
\n" ); document.write( "A shared work equation. Both will do a fraction of the job. The two fractions add up to 1
\n" ); document.write( " $\"3%2F7\"$ + $\"3%2Fc\"$ = 1
\n" ); document.write( "multiply by 7c
\n" ); document.write( "7c* $\"3%2F7\"$ + 7c* $\"3%2Fc\"$ = 7c*1
\n" ); document.write( "cancel the denominators and you have
\n" ); document.write( "3c + 7(3) = 7c
\n" ); document.write( "21 = 7c - 3c
\n" ); document.write( "21 = 4c
\n" ); document.write( "c = 21/4
\n" ); document.write( "c = 5.25 hr C working alone \n" ); document.write( "

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