document.write( "Question 950061: If the width of a certain rectangle is increased by 28 and the length is reduced by 39, we get a square with the same area as the original rectangle. Find the length and width of the original rectangle. \n" ); document.write( "
Algebra.Com's Answer #580079 by macston(5194)\"\" \"About 
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W=original width; L=original length
\n" ); document.write( "W+28=L-39 Add 39 to each side
\n" ); document.write( "W+67=L
\n" ); document.write( "L*W=(W+28)(L-39) Substitute for L
\n" ); document.write( "(W+67)(W)=(W+28)((W+67)-39)
\n" ); document.write( "(W^2+67W)=(W+28)(W+28)
\n" ); document.write( "W^2+67W=W^2+56W+784 Subtract W^2+56W from each side.
\n" ); document.write( "11W=784 Divide each side by 11.
\n" ); document.write( "W=71.27 The original width was 71.27
\n" ); document.write( "L=W+67=138.27 The original length was 138.27
\n" ); document.write( "ANSWER The original rectangle was 138.27 units by 71.27 units.
\n" ); document.write( "CHECK
\n" ); document.write( "L-39=138.27-39=99.27=Length of side of square.
\n" ); document.write( "W+28=71.27+28=99.27=length of side of square.
\n" ); document.write( "Areas are equal
\n" ); document.write( "L*W=S*s
\n" ); document.write( "138.27*71.27=99.27*99.27
\n" ); document.write( "9854.5 sq units=9854.5 sq units\r
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