document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=950063>Question 950063</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A person walks to the top of a mountain at a rate of 4mi/hr and down the mountain the same way at a rate of 3 mi/hr.  If she walks up and down in 2 hours, how far (mi) is it to the top?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #580069 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=580069\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d=distance to top; r1= rate up; r2=rate down; T=total time<BR>\n" );
document.write( "T=(d/r1)+(d/r2)<BR>\n" );
document.write( "2 hrs=d((1/r1)+(1/r2))<BR>\n" );
document.write( "2 hrs=d(1/4mph+1/3mph)<BR>\n" );
document.write( "2 hrs=d(3/12mph+4/12mph)<BR>\n" );
document.write( "2 hrs=d(7/12mph) Multiply each side by (12/7 mph)<BR>\n" );
document.write( "24/7 mi=d ANSWER: It is 3 and 3/7 miles to the top.<BR>\n" );
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document.write( "2 hrs=(24/7 mi/4 mph)+ (24/7 mi/3mph)<BR>\n" );
document.write( "2 hrs=(6/7 hrs)+(8/7 hrs)<BR>\n" );
document.write( "2 hrs=(14/7 hrs)<BR>\n" );
document.write( "2 hrs=2 hrs<BR>\n" );
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