document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=950032>Question 950032</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the 29th term of the following sequence.\r<BR>\n" );
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document.write( "2, 13, 24, 35, . . . </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #580034 by </B><A HREF=/tutors/aboutme.mpl?userid=erica65404><B>erica65404(394)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=erica65404><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=erica65404><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=580034\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the 29th term of the following sequence.\r<BR>\n" );
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document.write( "2, 13, 24, 35, . . .\r<BR>\n" );
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document.write( "Look for a pattern.<BR>\n" );
document.write( "Every time a term is added to the sequence, the term is 11 more than the number before. this means 11 is added each time.<BR>\n" );
document.write( "Since you start with 2 and the number goes up by 11 per term, the equation you would use to find the nth term would be 11n+2 where n is the number of the term you are looking for.\r<BR>\n" );
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document.write( "To find the 29th term, simply plug in 29\r<BR>\n" );
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document.write( "11n+2<BR>\n" );
document.write( "11(29)+2<BR>\n" );
document.write( "321\r<BR>\n" );
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document.write( "The 29th term is 321. </SPAN>\n" );
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