document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=949945>Question 949945</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two numbers have the sum of 79. One number is 10 more than twice the other number. Find the values of the numbers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #579990 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=579990\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's call the numbers x and 2x + 10. The problem says:<BR>\n" );
document.write( "x + 2x + 10 = 79 Add x's on the left and subtract 10 on both sides<BR>\n" );
document.write( "3x = 69<BR>\n" );
document.write( "x = 23 and 2(23) + 10 = 56\r<BR>\n" );
document.write( "\n" );
document.write( "Proof: 23 + 56 = 79 </SPAN>\n" );
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