document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=949947>Question 949947</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The  supplement of an angle is 10 degrees less than 3 times its compliment. Find the ratio of supplement to its compliment. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #579989 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=579989\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I don't know what you mean by compliment. Angles are either COMPLEMENTARY or SUPPLEMENTARY.\r<BR>\n" );
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document.write( "Supplementary angles are those that add up to 180 degrees.<BR>\n" );
document.write( "Let's call one angle x, and the problem says the supplement is 3(x - 10):\r<BR>\n" );
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document.write( "x + 3(x - 10) = 180 Simplify<BR>\n" );
document.write( "x + 3x - 30 = 180 Add x's on left. Also add 30, both sides.<BR>\n" );
document.write( "4x = 210<BR>\n" );
document.write( "x = 210/4<BR>\n" );
document.write( "x = 52 1/2 degrees. And the other is 3(52.5-10)= 127 1/2 degrees </SPAN>\n" );
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