document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=949946>Question 949946</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angels are complementary. One angle is 10 less than three times the other angle. Find the measure of both angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #579988 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=579988\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Complementary angles are those that add up to 90 degrees.\r<BR>\n" );
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document.write( "Let one angle be 3(x-10), just like the problem says. The other angle is just x.\r<BR>\n" );
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document.write( "x + 3(x - 10) = 90 Simplify<BR>\n" );
document.write( "x + 3x - 30 = 90 Add 30, both sides. Also add x's on the left<BR>\n" );
document.write( "4x = 120 Divide both sides by 4<BR>\n" );
document.write( "x = 30, and 3(30-10)= 60<BR>\n" );
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