document.write( "Question 80814: Two houses are for sale on the same street. The second house has 1000 square feet less than twice the square feet of the first house. Together the houses have 4400 square feet. What is the square footage of the first house? \n" ); document.write( "
Algebra.Com's Answer #57997 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
For the second house, you can write:
\n" ); document.write( "\"A%5B2%5D+=+2A%5B1%5D-1000\" where:\"A%5B1%5D\" and \"A%5B2%5D\" are the areas of house 1 and house 2 respectively. You can also write:
\n" ); document.write( "\"A%5B1%5D%2BA%5B2%5D+=+4400\" Rewrite this as: \"A%5B2%5D+=+4400-A%5B1%5D\" and substitute it for \"A%5B2%5D\" in the first equation.
\n" ); document.write( "\"4400-A%5B1%5D+=+2A%5B1%5D-1000\" Simplify and solve for \"A%5B1%5D\". Add \"A%5B1%5D\" to both sides.
\n" ); document.write( "\"4400+=+3A%5B1%5D+-1000\" Add 1000 to both sides.
\n" ); document.write( "\"5400+=+3A%5B1%5D\" Divide both sides by 3.
\n" ); document.write( "\"1800+=+A%5B1%5D\"\r
\n" ); document.write( "\n" ); document.write( "The first house has 1,800 square feet.
\n" ); document.write( "
\n" );