document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=949821>Question 949821</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find four consecutive integers such that the sum of twice the first and three times the third is 126. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #579897 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=579897\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> F=first integer; F+2=Third integer<BR>\n" );
document.write( "2F+3(F+2)=126<BR>\n" );
document.write( "2F+3F+6=126 Subtract 6 from each side.<BR>\n" );
document.write( "5F=120 Divide each side by 5<BR>\n" );
document.write( "F=24 ANSWER 1: The first integer is 24<BR>\n" );
document.write( "F+1=25 ANSWER 2: The second integer is 25<BR>\n" );
document.write( "F+2=26 ANSWER 3: Third integer is 26<BR>\n" );
document.write( "F+3=27 ANSWER 4: Fourth integer is 27<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "Twice first + 3 times Third = 126<BR>\n" );
document.write( "2(24)+3(26)=126<BR>\n" );
document.write( "48+78=126<BR>\n" );
document.write( "126=126<BR>\n" );
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