document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=949829>Question 949829</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the hypotenuse of a right angle triangle is 8 cm. if one leg is 2 cm longer than the other, find their lengths (2 decimal places) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #579896 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=579896\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the hypotenuse of a right angle triangle is 8 cm. if one leg is 2 cm longer than the other, find their lengths (2 decimal places)<BR>\n" );
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document.write( "Use Pythagoras::<BR>\n" );
document.write( "x^2 + (x+2)^2 = 8^2<BR>\n" );
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document.write( "x^2 + x^2 + 4x +4 = 64<BR>\n" );
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document.write( "2x^2 + 4x - 60 = 0<BR>\n" );
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document.write( "x^2 + 2x - 30 = 0<BR>\n" );
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document.write( "Positive solution::<BR>\n" );
document.write( "x = 4.57 cm<BR>\n" );
document.write( "x+2 = 6.47 cm<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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