document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=80620>Question 80620</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A snow storm lasts for 9 hours and dumps snow at a rate of 1.5 in./hr. If there was already 6 in. of snow on the ground before the storm, the snow depth is given by the equation: y = 3/2x +6, where y is the snow depth in inches and <BR>\n" );
document.write( "x is the time in hours.<BR>\n" );
document.write( "a)Find the snow depth at the end of the storm <BR>\n" );
document.write( "b) How long had it snowed when the total snow depth was 15in?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #57989 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=57989\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  snow storm lasts for 9 hours and dumps snow at a rate of 1.5 in./hr. If there was already 6 in. of snow on the ground before the storm, the snow depth is given by the equation: y = (3/2)x + 6, where y is the snow depth in inches and<BR>\n" );
document.write( "x is the time in hours.<BR>\n" );
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document.write( "a)Find the snow depth at the end of the storm<BR>\n" );
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document.write( "x is given as time so, substitute 9 for x in the equation y = (3/2)x + 6<BR>\n" );
document.write( "y = (3/2)*9 + 6<BR>\n" );
document.write( "y = (27/2) + 6<BR>\n" );
document.write( "y = 13.5 + x<BR>\n" );
document.write( "y = 19.5 inches in 9 hrs<BR>\n" );
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document.write( "b) How long had it snowed when the total snow depth was 15in?<BR>\n" );
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document.write( "Snow depth given as y so substitute 15 for y in the same equation;<BR>\n" );
document.write( "15 = (3/2)x + 6<BR>\n" );
document.write( "or<BR>\n" );
document.write( "1.5x + 6 = 15; decimal will work better here<BR>\n" );
document.write( "1.5x = 15 - 6; subtracted 6 from both sides<BR>\n" );
document.write( "1.5x = 9<BR>\n" );
document.write( "x = 9/1.5; divide both sides by 1.5<BR>\n" );
document.write( "x = 6 hrs<BR>\n" );
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document.write( "Check using x=6<BR>\n" );
document.write( "y = (3/2)6 + 6<BR>\n" );
document.write( "y = 9 + 6<BR>\n" );
document.write( "y = 15 inches  </SPAN>\n" );
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