document.write( "Question 949787: how can 48000 be invested part out of 5 percent annual simple interest in the remainder at 7 percent annual simple interest so that the interest earned by the two accounts will be equal \n" ); document.write( "
Algebra.Com's Answer #579884 by macston(5194)![]() ![]() You can put this solution on YOUR website! x=amount at 5%: y=amount at 7% \n" ); document.write( "x+y=48000 Subtract y from each side \n" ); document.write( "x=48000-y \n" ); document.write( "0.05x=0.07y Substitute for x \n" ); document.write( "0.05(48000-y)=0.07y \n" ); document.write( "2400-0.05y=0.07y Add 0.05y to each side. \n" ); document.write( "2400=0.12y Divide each side by 0.12 \n" ); document.write( "20000=y ANSWER 1: 20000 should be invested at 7%. \n" ); document.write( "x=48000-20000=28000 ANSWER 2: 28000 should be invested at 5%. \n" ); document.write( "CHECK: \n" ); document.write( "0.05(28000)=0.07(20000) \n" ); document.write( "1400=1400 \n" ); document.write( " \n" ); document.write( " |