document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=949678>Question 949678</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. the perimeter of a rectangle is 400cm. The length is 40cm longer than the width. find the length and width.\r<BR>\n" );
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document.write( "2. Jack is twice as old as lacy. In three years the sum of their ages will be 63. How old are they now?\r<BR>\n" );
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document.write( "3. The price of a swimming pool has been discounted 15%, the sale is 1000. find the original list price of the pol.\r<BR>\n" );
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document.write( "4. The product of two consecutive odd number is 14 more than the square of the smaller number, find the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #579825 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=579825\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> PROBLEM 1:<BR>\n" );
document.write( "W=width; L=length=W+40cm; P=perimeter=2(L+W)=400cm<BR>\n" );
document.write( "400cm=2(L+W) Divide each side by 2.<BR>\n" );
document.write( "200cm=L+W Substitute for L<BR>\n" );
document.write( "200cm=(W+40cm)+W Subtract 40cm from each side.<BR>\n" );
document.write( "160cm=2W Divide each side by 2.<BR>\n" );
document.write( "80cm=W  ANSWER 1: The width is 80 cm.<BR>\n" );
document.write( "L=w+40cm=80cm+40cm=120cm ANSWER 2: The length is 120 cm. <BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "400cm=2(120cm + 80cm)<BR>\n" );
document.write( "400cm=2(200 cm)<BR>\n" );
document.write( "400cm=400cm\r<BR>\n" );
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document.write( "PROBLEM 2:<BR>\n" );
document.write( "L=Lacy's age; J=Jack's age=2L<BR>\n" );
document.write( "If in 3 years the sum of their age will be 63, currently the sum is 57 (63-3years aging for each) <BR>\n" );
document.write( "J+L=57 years Substitute for J<BR>\n" );
document.write( "2L+L=57 years<BR>\n" );
document.write( "3L=57 years Divide each side by 3.<BR>\n" );
document.write( "L=19 years ANSWER 1: Lacy is 19 years old.<BR>\n" );
document.write( "J=2L=2(19 yrs)=38yrs ANSWER 2: Jack is 38 years old.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "(J+3 years)+(L+3 years)=63 years<BR>\n" );
document.write( "38 yrs+3 yrs+19 yrs+3 yrs=63 yrs<BR>\n" );
document.write( "63 yrs=63 yrs\r<BR>\n" );
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document.write( "PROBLEM 3:<BR>\n" );
document.write( "The pool is 85% of original price (100%-15%) so<BR>\n" );
document.write( "$1000/0.85=$1176.47 ANSWER: The original price was $1176.47.\r<BR>\n" );
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document.write( "PROBLEM 4:<BR>\n" );
document.write( "S=smaller number; S+2=larger number<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28S%29%28S%2B2%29=S%5E2%2B14 ALIGN=MIDDLE  ALT=\"%28S%29%28S%2B2%29=S%5E2%2B14\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S%5E2%2B2S=S%5E2%2B14 ALIGN=MIDDLE  ALT=\"S%5E2%2B2S=S%5E2%2B14\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract S^2 from each side.<BR>\n" );
document.write( "2S=14 Divide each side by 2.<BR>\n" );
document.write( "S=7 ANSWER 1: The smaller number is 7.<BR>\n" );
document.write( "S+2=9 ANSWER 2: The larger number is 9.<BR>\n" );
document.write( "CHECK<BR>\n" );
document.write( "Product of the two is 14 more than square of the smaller<BR>\n" );
document.write( "(7)(9)=(7)(7)+14<BR>\n" );
document.write( "63=49+14<BR>\n" );
document.write( "63=63\r<BR>\n" );
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document.write( " </SPAN>\n" );
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