document.write( "Question 949682: A book club offers a choice of 3 books from a list of 30. How many different selections of 3 different books each can be made from this list?\r
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document.write( "I TRIED 30*29*28= 24360 THEN DIVIDED THAT BY 3 AND GOT 8120
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document.write( "BUT IT WAS STILL WRONG. \n" );
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Algebra.Com's Answer #579808 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! A book club offers a choice of 3 books from a list of 30. How many different selections of 3 different books each can be made from this list? \n" ); document.write( "------------- \n" ); document.write( "The 1st choice is 1 of 30, then 29, then 28 \n" ); document.write( "--> 30*29*28 = 24360 \n" ); document.write( "---------- \n" ); document.write( "Choosing A, B & C is the same as A, C & B or C, B & A, etc. \n" ); document.write( "There are 6 possible arrangements for 3 books, 3*2*1 = 6 \n" ); document.write( "24360/6 = 4060 possibilities \n" ); document.write( " \n" ); document.write( " |