document.write( "Question 949682: A book club offers a choice of 3 books from a list of 30. How many different selections of 3 different books each can be made from this list?\r
\n" ); document.write( "\n" ); document.write( "I TRIED 30*29*28= 24360 THEN DIVIDED THAT BY 3 AND GOT 8120
\n" ); document.write( "BUT IT WAS STILL WRONG.
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Algebra.Com's Answer #579808 by Alan3354(69443)\"\" \"About 
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A book club offers a choice of 3 books from a list of 30. How many different selections of 3 different books each can be made from this list?
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\n" ); document.write( "The 1st choice is 1 of 30, then 29, then 28
\n" ); document.write( "--> 30*29*28 = 24360
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\n" ); document.write( "Choosing A, B & C is the same as A, C & B or C, B & A, etc.
\n" ); document.write( "There are 6 possible arrangements for 3 books, 3*2*1 = 6
\n" ); document.write( "24360/6 = 4060 possibilities
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