document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=949662>Question 949662</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two years ago the age of a man was four times the age of his son.3 years from now the age of the man will be 3 times the age of his son.find the age of each of them now<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #579806 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=579806\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> two years ago the age of a man was four times the age of his son.3 years from now the age of the man will be 3 times the age of his son.find the age of each of them now<BR>\n" );
document.write( "F=fathers age; S=son's age<BR>\n" );
document.write( "F-2=4(S-2)<BR>\n" );
document.write( "F-2=4S-8 Add 2 to each side<BR>\n" );
document.write( "F=4s-6 <BR>\n" );
document.write( "F+3=3(S+3) Substitute for F<BR>\n" );
document.write( "4S-6+3=3S+9 <BR>\n" );
document.write( "4S-3=3S+9 subtract 3S from each side,<BR>\n" );
document.write( "S-3=9 Add 3 to each side<BR>\n" );
document.write( "S=12 ANSWER 1: The son is 12 years old.<BR>\n" );
document.write( "F=4S-6=4(12)-6=48-6=42 ANSWER 2: The father is 42 years old.<BR>\n" );
document.write( "CHECK<BR>\n" );
document.write( "F-2=4(S-2)<BR>\n" );
document.write( "42-2=4(12-2)<BR>\n" );
document.write( "40=4(10)<BR>\n" );
document.write( "40=40\r<BR>\n" );
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