document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=949590>Question 949590</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive integers such that three times the first one is eight more than the sum of the last two integers  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #579758 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=579758\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive integers such that three times the first one is eight more than the sum of the last two integers <BR>\n" );
document.write( "First integer=x; second=x+1; third=x+2<BR>\n" );
document.write( "3x=((x+1)+(x+2))+8<BR>\n" );
document.write( "3x=2x+11 Subtract 2x from each side.<BR>\n" );
document.write( "x=11 ANSWER 1: The first number is 11<BR>\n" );
document.write( "x+1=12+1=12 ANSWER 2: The second number is 12<BR>\n" );
document.write( "x+2=12+2=13 ANSWER 3: The third number is 13<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "3 times first= 8 more than sum of last two<BR>\n" );
document.write( "3(11)=(12+13)+8<BR>\n" );
document.write( "33=25+8<BR>\n" );
document.write( "33=33 </SPAN>\n" );
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