document.write( "Question 949587: If the square of a positive number is increased by the number, the result is 12. What is the number ? \n" ); document.write( "
Algebra.Com's Answer #579750 by macston(5194)\"\" \"About 
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If the square of a positive number is increased by the number, the result is 12. What is the number ?
\n" ); document.write( "n= the number
\n" ); document.write( "\"n%5E2%2Bn=12\" Subtract 12 from each side.
\n" ); document.write( "\"n%5E2%2Bn-12=0\"\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"an%5E2%2Bbn%2Bc=0\" (in our case \"1n%5E2%2B1n%2B-12+=+0\") has the following solutons:
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\n" ); document.write( " \"n%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%281%29%5E2-4%2A1%2A-12=49\".
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\n" ); document.write( " Discriminant d=49 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-1%2B-sqrt%28+49+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"n%5B1%5D+=+%28-%281%29%2Bsqrt%28+49+%29%29%2F2%5C1+=+3\"
\n" ); document.write( " \"n%5B2%5D+=+%28-%281%29-sqrt%28+49+%29%29%2F2%5C1+=+-4\"
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\n" ); document.write( " Quadratic expression \"1n%5E2%2B1n%2B-12\" can be factored:
\n" ); document.write( " \"1n%5E2%2B1n%2B-12+=+1%28n-3%29%2A%28n--4%29\"
\n" ); document.write( " Again, the answer is: 3, -4.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B1%2Ax%2B-12+%29\"

\n" ); document.write( "\n" ); document.write( "ANSWER: Since we are looking for a positive number, the answer is 3
\n" ); document.write( "CHECK:
\n" ); document.write( "\"n%5E2%2Bn=12\"
\n" ); document.write( "\"3%5E2%2B3=12\"
\n" ); document.write( "\"9%2B3=12\"
\n" ); document.write( "\"12=12\"
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