document.write( "Question 949571: The length of a rectangle is 3 feet less than twice its width and area of rectangle is 27 ft2. Find the dimension\r
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Algebra.Com's Answer #579740 by macston(5194)![]() ![]() You can put this solution on YOUR website! W=width; L=length=2W-3 ft; A=L*W=27 sq ft \n" ); document.write( "A=L*W Substitute for L \n" ); document.write( "27 sq ft=(2W-3)(W) \n" ); document.write( " \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "ANSWER 1: W=4.5 ft The width is 4.5 feet. \n" ); document.write( "L=2W-3 ft=2(4.5)-3 ft=9 feet-3 feet=6 feet ANSWER 2: The length is 6 feet. \n" ); document.write( "CHECK: \n" ); document.write( "A=L*W \n" ); document.write( "27 sq ft=(6 ft)(4.5 ft) \n" ); document.write( "27 sq ft=27 sq ft \n" ); document.write( " |