document.write( "Question 949571: The length of a rectangle is 3 feet less than twice its width and area of rectangle is 27 ft2. Find the dimension\r
\n" ); document.write( "\n" ); document.write( "Lenth=\r
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Algebra.Com's Answer #579740 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
W=width; L=length=2W-3 ft; A=L*W=27 sq ft
\n" ); document.write( "A=L*W Substitute for L
\n" ); document.write( "27 sq ft=(2W-3)(W)
\n" ); document.write( "\"27+sq+ft=2W%5E2-3W\" Subtract 27 from each side
\n" ); document.write( "\"0=2W%5E2-3W-27\"\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"aW%5E2%2BbW%2Bc=0\" (in our case \"2W%5E2%2B-3W%2B-27+=+0\") has the following solutons:
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\n" ); document.write( " \"W%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-3%29%5E2-4%2A2%2A-27=225\".
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\n" ); document.write( " Discriminant d=225 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--3%2B-sqrt%28+225+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"W%5B1%5D+=+%28-%28-3%29%2Bsqrt%28+225+%29%29%2F2%5C2+=+4.5\"
\n" ); document.write( " \"W%5B2%5D+=+%28-%28-3%29-sqrt%28+225+%29%29%2F2%5C2+=+-3\"
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\n" ); document.write( " Quadratic expression \"2W%5E2%2B-3W%2B-27\" can be factored:
\n" ); document.write( " \"2W%5E2%2B-3W%2B-27+=+2%28W-4.5%29%2A%28W--3%29\"
\n" ); document.write( " Again, the answer is: 4.5, -3.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+2%2Ax%5E2%2B-3%2Ax%2B-27+%29\"

\n" ); document.write( "\n" ); document.write( "ANSWER 1: W=4.5 ft The width is 4.5 feet.
\n" ); document.write( "L=2W-3 ft=2(4.5)-3 ft=9 feet-3 feet=6 feet ANSWER 2: The length is 6 feet.
\n" ); document.write( "CHECK:
\n" ); document.write( "A=L*W
\n" ); document.write( "27 sq ft=(6 ft)(4.5 ft)
\n" ); document.write( "27 sq ft=27 sq ft
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