document.write( "Question 80641: Line l is the perpindicular bisector of AB, where A has coordinates (-2,3) and b has coordinates (5,4). Find the distance between the x and y intercepts of l. \n" ); document.write( "
Algebra.Com's Answer #57974 by ankor@dixie-net.com(22740)\"\" \"About 
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Line l is the perpendicular bisector of AB, where A has coordinates (-2,3) and b has coordinates (5,4). Find the distance between the x and y intercepts of l.\r
\n" ); document.write( "\n" ); document.write( "Here is the plan of attack on this problem. First find the mid-point of line AB.
\n" ); document.write( "This will be the point where line 1 crosses (bisects) AB, then we will find the
\n" ); document.write( "the slope (m1) of AB. From that we will find the slope (m2) of the line 1. Then,
\n" ); document.write( "using the midpoint coordinates and m2 slope find the equation of line 1. Then,
\n" ); document.write( "we can find the x & y intercepts of the line. Then find the distance between them.
\n" ); document.write( ":
\n" ); document.write( "Midpoint = \"%28x1%2Bx2%29%2F2\" and \"%28y1%2By2%29%2F2\"
\n" ); document.write( "M.P (x) = \"%285-2%29%2F2\" = \"3%2F2\"
\n" ); document.write( "M.P (y) = \"%284%2B3%29%2F2\" = \"7%2F2\"
\n" ); document.write( ":
\n" ); document.write( "x/y coordinates: 3/2, 7/2
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\n" ); document.write( ":
\n" ); document.write( "Find the slope (m1), of AB
\n" ); document.write( ":
\n" ); document.write( "m = \"%28%284+-+3%29%29%2F%28%285+-%28-2%29%29%29\" = \"%28%284+-+3%29%29%2F%28%285+%2B2+%29%29\" = \"%281%29%2F%287%29\"
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\n" ); document.write( "Find the slope (m2) of the perpendicular line:
\n" ); document.write( "We know the relationship of slopes of perpendicular lines is: m1*m2 = -1
\n" ); document.write( ":
\n" ); document.write( "(1/7) * m2 = -1
\n" ); document.write( ":
\n" ); document.write( "m2 = -7; multiplied both sides by 7
\n" ); document.write( ":
\n" ); document.write( "Find the equation of the line 1 using the point/slope formula; y-y1 = m(x-x1)
\n" ); document.write( "m2 = -7; y1 = 7/2; x1 = 3/2
\n" ); document.write( ":
\n" ); document.write( "y - (7/2) = -7(x - (3/2))
\n" ); document.write( "y - (7/2) = -7x + (21/2)
\n" ); document.write( "y = -7x + (21/2) + (7/2)
\n" ); document.write( "y = -7x + 28/2
\n" ); document.write( "y = -7x + 14
\n" ); document.write( ":
\n" ); document.write( "We know the y intercept (x=0) will be 14
\n" ); document.write( ":
\n" ); document.write( "Find the x intercept (y=0)
\n" ); document.write( "-7x + 14 = 0
\n" ); document.write( "-7x = -14
\n" ); document.write( "x = -14/-7
\n" ); document.write( "x = +2
\n" ); document.write( ":
\n" ); document.write( "WE can find the distance between the intercepts using pythag: a^2 + b^2 = c^2
\n" ); document.write( "Distance will be c:
\n" ); document.write( ":
\n" ); document.write( "c = Sqrt(2^2 + 14^2)
\n" ); document.write( "c = Sqrt(4 + 196)
\n" ); document.write( "c = Sqrt(200)
\n" ); document.write( "c = 14.142 is the distance between the intercepts\r
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\n" ); document.write( "\n" ); document.write( "Did this all makes sense to you, \r
\n" ); document.write( "\n" ); document.write( "Hope you did not get lost in the \"Heat of Battle!\"?\r
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