document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=949566>Question 949566</A>: <I><SPAN STYLE=\"word-break: break-all;\"> elmer is 25 years older than his son pablo; 15 yrs from now he will be twice as old as his son. find their present ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #579732 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=579732\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=Pablo's age; E=Elmer's age=P+25<BR>\n" );
document.write( "E+15=2(P+15) Substitute for E<BR>\n" );
document.write( "P+25+15=2P+30<BR>\n" );
document.write( "P+40=2P+30 Subtract P+30 from each side.<BR>\n" );
document.write( "10=P ANSWER 1: Pablo is 10 years old<BR>\n" );
document.write( "E=P+25=10+25=35 ANSWER 2: Elmer is 35 years old<BR>\n" );
document.write( "CHECK<BR>\n" );
document.write( "E+15=2(P+15)<BR>\n" );
document.write( "35+15=2(10+15)<BR>\n" );
document.write( "50=2(25)<BR>\n" );
document.write( "50=50<BR>\n" );
document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );