document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=949560>Question 949560</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cyclists leave towns 78 mi apart at the same time and travel toward each other. One cyclist travels 3 mi/h slower than the other. If they meet in 2 hours, what is the rate of each cyclist? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #579730 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=579730\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The combined rate of the cyclists is 78 mi/2hrs=39 mi/hr<BR>\n" );
document.write( "Cyclist one travels (r-3)mph, cyclist two travels at (r)mph<BR>\n" );
document.write( "(r-3)+r=39 mi/hr<BR>\n" );
document.write( "2r-3=39 mph<BR>\n" );
document.write( "2r=42 mph<BR>\n" );
document.write( "r=21 mph ANSWER Cyclist 2 travels at 21 mph.<BR>\n" );
document.write( "(r-3)=(21-3)=18 mph ANSWER Cyclist 1 travels at 18 mph\r<BR>\n" );
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