document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=949541>Question 949541</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is three times its width. If the perimeter of the rectangle is 64m, find its area </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #579717 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=579717\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter equals 2 times the length plus 2 times the width:\r<BR>\n" );
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document.write( "2L + 2W = Perimeter, which in your problem is 64\r<BR>\n" );
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document.write( "And since the length is 3 times the width, we can say that:\r<BR>\n" );
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document.write( "L = 3W Now, using this information we re-write the first equation:\r<BR>\n" );
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document.write( "3(2W) + 2W = 64 simplify:<BR>\n" );
document.write( "6W + 2W = 64 Add on the left:<BR>\n" );
document.write( "8W = 64 Now divide both sides by 8:<BR>\n" );
document.write( "W= 8<BR>\n" );
document.write( "Proof: 3(2*8) + 2*8 = 64; 48 + 16 = 64 We have the correct answer.<BR>\n" );
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