document.write( "Question 949522: John is presently 12 years older than Fred. Four years ago John was twice as old as Fred. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #579708 by macston(5194)![]() ![]() You can put this solution on YOUR website! J=John's age=F+12 years: F=Fred's age \n" ); document.write( "J-4 years=2(F-4 years) Substitute for J \n" ); document.write( "F+12 years-4 years=2(F-4 years) \n" ); document.write( "F+8=2F-8 years Add 8 years to each side. \n" ); document.write( "F+16 years=2F Subtract F from each side. \n" ); document.write( "16 years=F ANSWER: Fred is currently 16 years old. \n" ); document.write( "J=F+12 years=16 years+12 years=28 years ANSWER: John is currently 28 years old. \n" ); document.write( "CHECK: \n" ); document.write( "J-4 years=2(F-4 years) \n" ); document.write( "28 years-4 years=2(16 years-4 years) \n" ); document.write( "24 years=2(12 years) \n" ); document.write( "24 years=24 years \n" ); document.write( " |