document.write( "Question 949522: John is presently 12 years older than Fred. Four years ago John was twice as old as Fred. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #579708 by macston(5194)\"\" \"About 
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J=John's age=F+12 years: F=Fred's age
\n" ); document.write( "J-4 years=2(F-4 years) Substitute for J
\n" ); document.write( "F+12 years-4 years=2(F-4 years)
\n" ); document.write( "F+8=2F-8 years Add 8 years to each side.
\n" ); document.write( "F+16 years=2F Subtract F from each side.
\n" ); document.write( "16 years=F ANSWER: Fred is currently 16 years old.
\n" ); document.write( "J=F+12 years=16 years+12 years=28 years ANSWER: John is currently 28 years old.
\n" ); document.write( "CHECK:
\n" ); document.write( "J-4 years=2(F-4 years)
\n" ); document.write( "28 years-4 years=2(16 years-4 years)
\n" ); document.write( "24 years=2(12 years)
\n" ); document.write( "24 years=24 years
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