document.write( "Question 949492: Suppose the line through points (n,6) and (1,2) is parallel to the graph of 2x+y=3. Find the value of n.
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Algebra.Com's Answer #579672 by MathLover1(20850)\"\" \"About 
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Suppose the line through points (\"n\",\"6\") and (\"1\",\"2\") is parallel to the graph of \"2x%2By=3\". Find the value of \"n\".\r
\n" ); document.write( "\n" ); document.write( "you are looking for \"y=mx%2Bb\" parallel to the graph of \"2x%2By=3\"
\n" ); document.write( "parallel lines have same slope, so find slope of the line \"2x%2By=3\" \r
\n" ); document.write( "\n" ); document.write( "\"y=-2x%2B3\"-> slope \"m=-2\"\r
\n" ); document.write( "\n" ); document.write( "so far we have \"y=-2x%2Bb\"\r
\n" ); document.write( "\n" ); document.write( "if the line passes through point(\"1\",\"2\"), then we can use it to find y-intercept \"b\"\r
\n" ); document.write( "\n" ); document.write( "\"2=-2%2A1%2Bb\"\r
\n" ); document.write( "\n" ); document.write( "\"2=-2%2Bb\"\r
\n" ); document.write( "\n" ); document.write( "\"2%2B2=b\"\r
\n" ); document.write( "\n" ); document.write( "\"b=4\"\r
\n" ); document.write( "\n" ); document.write( "so, our line is \"y=-2x%2B4\"\r
\n" ); document.write( "\n" ); document.write( "if the line passes through point(\"n\",\"6\"), then \"x=n\" and \"y=6\", so plug it in \"y=-2x%2B4\" and solve for \"n\"\r
\n" ); document.write( "\n" ); document.write( " \"6=-2n%2B4\"\r
\n" ); document.write( "\n" ); document.write( "\"2n=-6%2B4\"\r
\n" ); document.write( "\n" ); document.write( "\"2n=-2\"\r
\n" ); document.write( "\n" ); document.write( "\"n=-1\"\r
\n" ); document.write( "\n" ); document.write( "so, the line passes through point(\"-1\",\"6\")\r
\n" ); document.write( "\n" ); document.write( "check it on a graph:\r
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