document.write( "Question 949497: 5-2x=sqrt(3x+10) \n" ); document.write( "

Algebra.Com's Answer #579669 by stanbon(75887) $\"\"$ $\"About$

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5-2x=sqrt(3x+10)
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\n" ); document.write( "Square both sides::
\n" ); document.write( "25-20x+4x^2 = 3x+10
\n" ); document.write( "4x^2 - 23x + 15 = 0
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\n" ); document.write( "(x-5)(4x-3) = 0
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\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 3/4
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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