document.write( "Question 949485: prove the identities 1/(〖tan〗^2 ϴ+1)+1/(〖cot〗^2 ϴ+1)=1\r
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document.write( "i know tan^2 ϴ+1 = sec^2 ϴ
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document.write( "and cot^2 ϴ+1 = csc^2 ϴ
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document.write( " then sec^2 ϴ is (1/cosϴ)^2
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document.write( "and csc^2 ϴ is (1/sinϴ)^2
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document.write( "cos^2 ϴ + sin^2 ϴ = 1
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document.write( "please help ... to prove \n" );
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Algebra.Com's Answer #579666 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! prove the identities 1/(〖tan〗^2 ϴ+1)+1/(〖cot〗^2 ϴ+1)=1\r \n" ); document.write( "\n" ); document.write( "i know tan^2 ϴ+1 = sec^2 ϴ \n" ); document.write( "and cot^2 ϴ+1 = csc^2 ϴ \n" ); document.write( " then sec^2 ϴ is (1/cosϴ)^2 \n" ); document.write( "and csc^2 ϴ is (1/sinϴ)^2 \n" ); document.write( "cos^2 ϴ + sin^2 ϴ = 1 \n" ); document.write( "please help ... to prove \n" ); document.write( "=============== \n" ); document.write( "1 more step: \n" ); document.write( "1 = 1 \n" ); document.write( "sin^2 + cos^2 = 1 is the Pythagorean Identity. \n" ); document.write( "---- \n" ); document.write( "i know tan^2 + 1 = sec^2 \n" ); document.write( "Multiply thru by cos^2 \n" ); document.write( "sin^2 + cos^2 = 1 \n" ); document.write( " \n" ); document.write( " |