document.write( "Question 949485: prove the identities 1/(〖tan〗^2 ϴ+1)+1/(〖cot〗^2 ϴ+1)=1\r
\n" ); document.write( "\n" ); document.write( "i know tan^2 ϴ+1 = sec^2 ϴ
\n" ); document.write( "and cot^2 ϴ+1 = csc^2 ϴ
\n" ); document.write( " then sec^2 ϴ is (1/cosϴ)^2
\n" ); document.write( "and csc^2 ϴ is (1/sinϴ)^2
\n" ); document.write( "cos^2 ϴ + sin^2 ϴ = 1
\n" ); document.write( "please help ... to prove
\n" ); document.write( "

Algebra.Com's Answer #579666 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
prove the identities 1/(〖tan〗^2 ϴ+1)+1/(〖cot〗^2 ϴ+1)=1\r
\n" ); document.write( "\n" ); document.write( "i know tan^2 ϴ+1 = sec^2 ϴ
\n" ); document.write( "and cot^2 ϴ+1 = csc^2 ϴ
\n" ); document.write( " then sec^2 ϴ is (1/cosϴ)^2
\n" ); document.write( "and csc^2 ϴ is (1/sinϴ)^2
\n" ); document.write( "cos^2 ϴ + sin^2 ϴ = 1
\n" ); document.write( "please help ... to prove
\n" ); document.write( "===============
\n" ); document.write( "1 more step:
\n" ); document.write( "1 = 1
\n" ); document.write( "sin^2 + cos^2 = 1 is the Pythagorean Identity.
\n" ); document.write( "----
\n" ); document.write( "i know tan^2 + 1 = sec^2
\n" ); document.write( "Multiply thru by cos^2
\n" ); document.write( "sin^2 + cos^2 = 1
\n" ); document.write( "
\n" ); document.write( "
\n" );