document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=949475>Question 949475</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can you help me with this problem\r<BR>\n" );
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document.write( "cosxsinx - 2cosx = 0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #579662 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=579662\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "cosxsinx - 2cosx = 0 <BR>\n" );
document.write( "cosx(sinx-2)=0 divide each side by cosx<BR>\n" );
document.write( "sinx-2=0 Subtract 2 from each side<BR>\n" );
document.write( "sinx=2 No solution: sine of an angle cannot be greater than 1 because the length of a leg of a right triangle cannot be greater than the hypotenuse<BR>\n" );
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