document.write( "Question 949479: A rectangle is 3 times as long as its width. If the perimeter is 104ft, what is it's dimension? \n" ); document.write( "
Algebra.Com's Answer #579660 by macston(5194) You can put this solution on YOUR website! A rectangle is 3 times as long as its width. If the perimeter is 104ft, what is it's dimension? \n" ); document.write( "W=width; L=length=3W; P=perimeter=2(L+W) \n" ); document.write( "P=2(L+W) \n" ); document.write( "104 ft=2(L+W) Divide each side by 2. \n" ); document.write( "52 ft=L+W Substitute for L \n" ); document.write( "52 ft=3W+W=4W divide each side by 4 \n" ); document.write( "13 ft=W ANSWER 1: Width is 13 ft \n" ); document.write( "L=3W=3(13 ft)=39 ft ANSWER 2: Length is 39 ft. \n" ); document.write( "CHECK: \n" ); document.write( "2(L+W)=perimeter \n" ); document.write( "2(39 ft+13 ft)=104 ft \n" ); document.write( "2(52 ft)=104 ft \n" ); document.write( "104 ft=104 ft \n" ); document.write( " |