document.write( "Question 80809: A man has a barn that is 20 ft by 10 ft. He tethers a cow to one corner of the outside of the barn using a 50-ft rope. \r
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document.write( "What is the total area that the cow is capable of grazing?
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document.write( "Please show me how you got the answer as well thank you \n" );
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Algebra.Com's Answer #57965 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Draw the picture. Draw the post (center) and the circle with 50 ft radius. \n" ); document.write( "Draw the corner of the barn that cuts off 1/4 of the area of the circle. \n" ); document.write( "Now do the math: \n" ); document.write( "Area of the circle = (pi)50^2 sq ft. = 2500(pi) sq ft \n" ); document.write( "Only (3/4)(2500(pi)) is available for grazing. \n" ); document.write( "That area is 1875(pi) sq ft = 5890.49 sq ft \n" ); document.write( "============= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |