document.write( "Question 80809: A man has a barn that is 20 ft by 10 ft. He tethers a cow to one corner of the outside of the barn using a 50-ft rope. \r
\n" ); document.write( "\n" ); document.write( "What is the total area that the cow is capable of grazing?
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\n" ); document.write( "Please show me how you got the answer as well thank you
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Algebra.Com's Answer #57965 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Draw the picture. Draw the post (center) and the circle with 50 ft radius.
\n" ); document.write( "Draw the corner of the barn that cuts off 1/4 of the area of the circle.
\n" ); document.write( "Now do the math:
\n" ); document.write( "Area of the circle = (pi)50^2 sq ft. = 2500(pi) sq ft
\n" ); document.write( "Only (3/4)(2500(pi)) is available for grazing.
\n" ); document.write( "That area is 1875(pi) sq ft = 5890.49 sq ft
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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