document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=949448>Question 949448</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Show work of -2x - 15 < or equal to 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #579649 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=579649\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -2x - 15 < = 3<BR>\n" );
document.write( "multiply each term by -1, this reverses the inequality sign<BR>\n" );
document.write( "2x + 15 >= -3<BR>\n" );
document.write( "2x  >= - 3 - 15<BR>\n" );
document.write( "2x >- -18<BR>\n" );
document.write( "x >= -18/2<BR>\n" );
document.write( "x >= -9 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );