document.write( "Question 948467: Locate the center, foci, vertices, ends of latera recta, & draw the ellipse. also compute the eccentricity & find the equation of the directices. \r
\n" ); document.write( "\n" ); document.write( "2.x^2/36+y^2/16=1
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Algebra.Com's Answer #579644 by macston(5194)\"\" \"About 
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\"x%5E2%2F36%2By%5E2%2F16=1\"\r
\n" ); document.write( "\n" ); document.write( "STANDARD FORM:
\n" ); document.write( "\"%28x-h%29%5E2%2F%28a%5E2%29%2B%28y-k%29%5E2%2F%28b%5E2%29=1\"\r
\n" ); document.write( "\n" ); document.write( "CENTER: Center is at (h,k) in this case (0,0). Center is at origin.\r
\n" ); document.write( "\n" ); document.write( "FOCI: Focus is (f) from center \"f%5E2=a%5E2-b%5E2\"
\n" ); document.write( "\"f%5E2=36-16=20\" Find square root of each side.
\n" ); document.write( "\"f=sqrt%2820%29\"
\n" ); document.write( " Foci are at (\"-sqrt%2820%29\",\"0\") and (\"sqrt%2820%29\",\"0\"). \r
\n" ); document.write( "\n" ); document.write( "VERTICES: In this case at (+ or - a,0) and a=\"sqrt%2836%29\"=6
\n" ); document.write( " Vertices at (-6,0) and (6,0)\r
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\n" ); document.write( "\n" ); document.write( "ENDPOINTS OF LATERA RECTA: The latera recta are perpendicular to the major axis at the foci, and have length: \"2b%5E2%2Fa\". Since half is above and half is below the axis, we need half the length or \"b%5E2%2Fa\"=16/6=8/3
\n" ); document.write( "For the focus at (\"-sqrt%2820%29\"),\"0\"), the endpoints of the latus rectum are (\"-sqrt%2820%29\",\"%288%2F3%29\") and (\"-sqrt%2820%29\",\"-%288%2F3%29\")
\n" ); document.write( "For the focus at (\"sqrt%2820%29\",\"0\"), the endpoints of the latus rectum are (\"sqrt%2820%29\",\"%288%2F3%29\") and (\"sqrt%2820%29\",\"-%288%2F3%29\")\r
\n" ); document.write( "\n" ); document.write( "ECCENTRICITY: Eccentricity \"epsilon\"=f/a=\"sqrt%2820%29%2F6\"\r
\n" ); document.write( "\n" ); document.write( "EQUATIONS OF DIRECTRICES: directrix is a line perpendicular to the main axis
\n" ); document.write( "on opposite the vertex from the focus, and same distance as the focus from the vertex. The directrix is outside the ellipse. The is a+(a-f) from the center,
\n" ); document.write( "or in this case, the directrix to the right of the origin is x=\"6%2B%286-sqrt%2820%29%29\"=\"12-sqrt%2820%29\" and to the left of the origin x=-(\"12-sqrt%2820%29\"). \r
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