document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=949387>Question 949387</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Describe the end-behavior of the given function;(Hint: rearrange the terms)<BR>\n" );
document.write( "f(x)= -3x + 5x^3 - 12 - 2x^9<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #579626 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=579626\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Describe the end-behavior of the given function;(Hint: rearrange the terms)<BR>\n" );
document.write( " f(x)= -3x + 5x^3 - 12 - 2x^9<BR>\n" );
document.write( " ------<BR>\n" );
document.write( "Note:: The highest power term will determine the end-behaviour.<BR>\n" );
document.write( "----<BR>\n" );
document.write( "As x approaches -oo, -2x^9 approaches +oo<BR>\n" );
document.write( "As x approaches +oo, -2x^9 approaches -oo<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );