document.write( "Question 949379: Show your method used to solve problem.
\n" ); document.write( "If the cost of 5 roses, 9 irises and 6 carnations is the same as 3 carnations 6 irises and 8 roses find the cost of a single iris if it cost $42 for a dozen roses and a carnation is three-quarters the cost of an iris.
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Algebra.Com's Answer #579603 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "Show your method used to solve problem.
\n" ); document.write( "If the cost of 5 roses, 9 irises and 6 carnations is the same as 3 carnations 6 irises and 8 roses find the cost of a single iris if it cost $42 for a dozen roses and a carnation is three-quarters the cost of an iris.
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\n" ); document.write( "Let price of 1 rose, 1 iris and 1 carnation be R, I, and C, respectively
\n" ); document.write( "Then we can say that: 5R + 9I + 6C = 8R + 6I + 3C
\n" ); document.write( "8R - 5R + 6I - 9I + 3C - 6C = 0
\n" ); document.write( "3R - 3I - 3C = 0
\n" ); document.write( "3(R - I - C) = 3(0) ------ Factoring out GCF, 3
\n" ); document.write( "R - I - C = 0 ------- eq (i)\r
\n" ); document.write( "\n" ); document.write( "12R = 42
\n" ); document.write( "R, or cost of 1 rose = \"42%2F12\", or $3.50\r
\n" ); document.write( "\n" ); document.write( "\"C+=+%283%2F4%29I\"_____\"C+=+3I%2F4\" ------- Cost of 1 carnation is \"3%2F4\" cost of an iris \r
\n" ); document.write( "\n" ); document.write( "R - I - C = 0 -------- eq (i)
\n" ); document.write( "\"3.5+-+4I+-+3I%2F4+=+0\"-------- Substituting 3.5 for R, and \"3I%2F4\" for C in eq (i)
\n" ); document.write( "\"14+-+4I+-+3I+=+0\" -------- Multiplying by LCD, 4
\n" ); document.write( "14 - 7I = 0
\n" ); document.write( "14 = 7I
\n" ); document.write( "Cost of 1 iris = \"14%2F7\", or \"highlight_green%28I+=+%22%24%222%29\" \n" ); document.write( "
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